\(\frac{x+1}{2}=\frac{8}{x+1}\)
=> (x + 1)(x + 1) = 8.2
=> (x + 1)2 = 16
=> x + 1 = 4 hoặc x + 1 = - 4
=> x = 3 hoặc x = - 5
\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=8.2\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow\left(x+1\right)^2=4^2\)
\(\Rightarrow x+1=4\)
\(\Rightarrow x=3\)
=>(x+1).(x+1)=8.2
(x+1)\(^2\)=16
(x+1)\(^2\)=4\(^2\)
=>x+1=4
x=4-1
x=3
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