Question

tìm x biết: 

\(\frac{x-3}{-2}=\frac{-6}{x-3}\)

Answer 1

\(\frac{x-3}{-2}=\frac{-6}{x-3}\Rightarrow\left(x-3\right)^2=12\)

Th1: 

\(x-3=\sqrt{12}\Rightarrow x=\sqrt{12}+3\)

Th2: 

\(x-3=-\sqrt{12}\Rightarrow x=-\sqrt{12}+3\)

Answer 2

suy ra: x-3.x-3=-2.-6

suy ra: x-3.x-3=12

suy ra: x-3.x=12:3

suy ra: x-3.x=4

suy ra: 2x=4:3

suy ra: 2x=0.5

suy ra: x =0.5:2

suy ra: x=0,25

Answer 3

<=>(x-3)(x-3)=12     <=> X²-6X+9-12=0 <=> X²-6X-3=0 <=> X=3+2\(\sqrt{3}\), X=3-2\(\sqrt{3}\)