Question

tìm x biết :

\(\frac{x}{-2}=\frac{-8}{x}\)

 

Answer 1

\(\frac{x}{-2}=\frac{-8}{x}\Leftrightarrow x^2=\left(-2\right).\left(-8\right)=16=4^2;\left(-4\right)^2\Rightarrow x=\left\{4;-4\right\}\)

Answer 2

\(\frac{x}{-2}=\frac{-8}{x}\Rightarrow x^2=16\Leftrightarrow\text{[}x=4;x=-4\text{]}\)

Answer 3

Ta có:\(\frac{x}{-2}=\frac{-8}{x}\)

\(\Rightarrow x.x=\left(-8\right).\left(-2\right)\)

\(\Rightarrow x^2=16\)

\(\Rightarrow x^2=4^2\) hoặc \(x^2=\left(-4\right)^2\)

\(\Rightarrow x=4\) hoặc \(x=-4\)

Answer 4

x bằng 4 hoặc bằng -4

Answer 5

X/-2=-8/x

<=>x^2=(-2).(-8)=16

<=> x E {-4;4}

 vậy...