\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
=>\(\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x+2\right)\)
=>\(x^2+2x-3=x^2-4\)
=>\(x^2+2x-x^2=-4+3\) (quy tắc chuyển vế)
=>\(2x=-1\)
=>\(x=\frac{-1}{2}\)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right).\left(x+3\right)=\left(x+2\right).\left(x-2\right)\)
\(\Rightarrow x^2+3x-x-3=x^2-2^2\)
\(\Rightarrow3x-x-3=4\)
\(\Rightarrow2x-3=4\)
\(\Rightarrow2x=7\)
\(\Rightarrow x=\frac{7}{2}\)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Leftrightarrow\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x-2\right)\)
\(\Leftrightarrow x^2+2x-3=x^2-4\)
\(\Leftrightarrow x^2-x^2+2x=-4+3\)
\(\Leftrightarrow2x=-1\)
\(\Leftrightarrow x=-\frac{1}{2}\)
(Nhớ k cho mình với nha!)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
=> \(\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x+2\right)\)
=> \(x^2+2x-3=x^2-4\)
=> \(x^2+2x-x^2=4+3\)
=> \(2x=-1\)
=> \(x=\frac{-1}{2}\)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+3x-x-3=x^2-2^2\)
\(\Rightarrow x^2-2x-3=x^2-4\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=\frac{-1}{2}\)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(=>\left(x-1\right).\left(x+3\right)=\left(x+2\right).\left(x-2\right)\)
\(=>x^2+3x-x-3=x^2-2x+2x-4\)
\(x^2+2x-3=x^2-4\)
\(=>2x+3=-4\)
\(2x=-4+3=>2x=-1=>x=-\frac{1}{2}\)
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Leftrightarrow\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x+2\right)\)
\(\Leftrightarrow x^2+2x-3=x^2-4\)
\(\Leftrightarrow2x+1=0\)
\(\Leftrightarrow2x=0-1=\left(-1\right)\)
\(\Leftrightarrow x=\left(-1\right):2=\left(-0,5\right)\)
Chúc bạn học tốt !!!
trả lời
=-1/2
chúc bn
học tốt
nghĩ lại hồi đs spam là ko tốt :v
\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\left(x-1\right)\left(x+3\right)=\left(x-2\right)\left(x-2\right)\)
\(x^2+3x-x-3=x^2-2x+2x-4\)
\(x^2-2x-3=x^2-4\)
\(x^2-2x-3-x^2+4=0\)
\(-2x+1=0\)
\(-2x=-1\Rightarrow x=\frac{1}{2}\)
