tìm x biết
=>(x−1)2.2 =24.3
[x-1]2.2=72
[x-1]2=72:2
[x-1]2=36
[x-1]2=62
=>x-1=6
x=6+1
x=7
\(\frac{\left(x-1\right)^2}{3}=\frac{24}{2}\)
\(\frac{\left(x-1\right)^2}{3}=12\)
\(\left(x-1\right)^2=12\cdot3\)
\(\left(x-1\right)^2=36\)
\(\Rightarrow\left(x-1\right)^2=+-6^2\)
+) x-1=6
x=7
x-1=-6
x=-6+1
x=-5
Vậy x=7 và x=-5