Question

Tìm x biết:      \(\frac{1}{5\times8}+\frac{1}{8\times11}+\frac{1}{11\times14}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)

Answer 1

\(\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)

\(\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{101}{1540}\)

\(\frac{1}{3}\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{101}{1540}\)

\(\frac{1}{5}-\frac{1}{x+3}=\frac{101}{4620}\)

\(\frac{1}{x+3}=\frac{823}{4620}\)

Answer 2

\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x\left(x+3\right)}=\frac{101}{1540}\)

\(=\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x\left(x+3\right)}\right)=\frac{101}{1540}\)

\(=\frac{1}{3}\left(\frac{1}{5}-\frac{1}{x+3}\right)\)

\(=\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)

\(=\frac{1}{x+3}=\frac{1}{308}\)

Answer 3

aloalo

Answer 4

Câu có vẻ khó 

Answer 5

em chịu