Question

Tìm x, biết: \(\frac{1+3y}{12}\)= \(\frac{1+6y}{16}\)= \(\frac{1+9y}{4x}\)

Answer 1

x=5 

Vì y=1/6

Answer 2

WHAT?

Answer 3

Answer 4

Answer 5

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Answer 6

\(\frac{1+3y}{12}=\frac{1+6y}{16}=\frac{1+9y}{4x}\)

\(=\frac{\left(1+6y\right)-\left(1+3y\right)}{16-12}=\frac{\left(1+9y\right)-\left(1+6y\right)}{4x-16}\)

\(=\frac{3y}{4}=\frac{3y}{4x-16}\)(1)

\(\text{TH1 Nếu y=0}\)

\(\Rightarrow\frac{1}{12}=\frac{1}{16}\left(\text{vô lí}\right)\)

\(\text{TH2 nếu y khác 0}\)

\(\text{(1)}\Rightarrow4x-16=4\)

\(\Rightarrow x=5\)

\(\text{Với x=5 }\)

\(\Rightarrow\frac{1+6y}{16}=\frac{1+9y}{4.5}\)

\(\Rightarrow\frac{1+6y}{16}=\frac{1+9y}{20}\)

\(\Rightarrow5\left(1+6y\right)=4\left(1+9y\right)\)

\(\Rightarrow5+30y=4+36y\)

\(\Rightarrow1=6y\)

\(\Rightarrow y=\frac{1}{6}\)

\(\text{Vậy x=5, y=}\frac{1}{6}\)

Answer 7

TTk mk nha bạn