Question

Tìm x biết :  \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)

Answer 1

Áp dụng tính chất dãy tỉ số bằng nhau, ta có:

\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{18+6x}=\frac{2\left(1+4y\right)}{2\left(9+3x\right)}=\frac{1+4y}{9+3x}\)

suy ra: \(\frac{1+4y}{9+3x}=\frac{1+4y}{24}\Rightarrow9+3x=24\Rightarrow3x=15\Rightarrow x=5\)

Answer 2

\(\frac{1+4y}{24}=\frac{1+6y}{6x}\)=>\(\frac{1+4y+2y}{24+2y}=\frac{1+6y}{2x}\)=>\(2y+24=6x\)=>\(y+12=3x\)=>\(y=3x-12\)

=>\(\frac{1+6x-24}{18}=\frac{1+6y}{6x}\)=>\(\frac{6x-23}{18}=\frac{6y+1}{6x}\)=>\(6x\left(6x-23\right)=18\left(6y+1\right)\)

=>\(36x^2-\)

Answer 3

mấy bạn kia làm đúng rồi

Answer 4

Mấy bạn kia làm đúng rồi

k nha các bạn^_^&>_<

Answer 5

x=5 lầ đúng đảm bảo luôn

Answer 6

vậy y = bao nhiêu

Answer 7

tìm x,y biết \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)

Answer 8

\(\frac{1+2y}{18}=\frac{2+4y}{36}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{2+4y-1-4y}{36-24}\)

\(=\frac{1}{12}\)

\(\Rightarrow\frac{1+2y}{18}=\frac{1}{12}\Rightarrow1+2y=\frac{18}{12}=\frac{3}{2}\)

\(\Rightarrow2y=\frac{1}{2}\Rightarrow y=\frac{1}{4}\)

Answer 9

Nhầm:D

\(\frac{1+6y}{6x}=\frac{1}{12}\Rightarrow\frac{1+6y}{6}=\frac{x}{12}\)

\(=>\frac{1}{6}+y=\frac{x}{12}\)

\(\Rightarrow\frac{1}{6}+\frac{1}{4}=\frac{x}{12}\Rightarrow\frac{x}{12}=\frac{5}{12}\Rightarrow x=5\)

Answer 10

đáp án

x = 6

hok 

k cho minh

Answer 11

\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)

\(\Leftrightarrow\frac{1+2y}{\frac{6}{\frac{18}{6}}}=\frac{1+4y}{\frac{6}{\frac{24}{6}}}=\frac{1+6y}{6x}\)

\(\Leftrightarrow\frac{1+2y}{2}=\frac{1+4y}{\frac{3}{2}}=\frac{1+6y}{6x}\)

\(\Leftrightarrow\frac{\left(1+2y\right).6}{12}=\frac{\left(1+4y\right).8}{12}=\frac{1+6y}{6x}\)

\(\Leftrightarrow\frac{\left(1+2y\right).6}{12}=\frac{1+6y}{6x}\)

\(\Leftrightarrow\frac{\left(1+2y\right).6}{12}=\frac{\left(1+6y\right).2}{12}\Leftrightarrow x=2\)

bừa :v