Ta có :
\(\frac{1}{2}+-\frac{3}{4}< x\le\frac{1}{5}+1\frac{4}{5}\)
\(\Rightarrow\frac{2}{4}+-\frac{3}{4}< x\le\frac{1}{5}+\frac{9}{5}\)
\(\Rightarrow\frac{-1}{4}< x\le\frac{10}{5}\)
\(\Rightarrow\frac{-1}{4}< x\le2\)
Mà \(x\in Z\)
\(\Rightarrow x\in\left\{0;1;2\right\}\)
Đ/k x thiếu :
x thuộc Z là mik tự nghĩ ra đấy
\(\frac{1}{2}+\frac{-3}{4}< x\le\frac{1}{5}+1\frac{4}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{4}< x\le\frac{1}{5}+\frac{9}{5}\)
\(\Rightarrow\frac{-1}{4}< x\le2\)
\(\Rightarrow\frac{-1}{4}< x\le\frac{8}{4}\)
\(\Rightarrow x\in\left\{0;\frac{1}{4};\frac{1}{2};\frac{3}{4};1;\frac{5}{4};\frac{3}{2};\frac{7}{4};2\right\}\)
Vậy \(x\in\left\{0;\frac{1}{4};\frac{1}{2};\frac{3}{4};1;\frac{5}{4};\frac{3}{2};\frac{7}{4};2\right\}\)
_Chúc bạn học tốt_
\(\Rightarrow\frac{-1}{4}< x\le2\)
\(\Rightarrow\frac{-1}{4}< x\le\frac{8}{4}\)
mà \(x\in Z\)
\(\Rightarrow x\in\left\{0;1;2\right\}\)
