\(\dfrac{6}{x}=\dfrac{24}{x-7}\left(x\ne0;x\ne27\right)\)
suy ra
`6(x-27)=24x`
`=>6x-162-24x=0`
`=>-18x=162`
`=>x=-9(tm)`
\(\dfrac{6}{x}=\dfrac{24}{x-27}\left(dkxd:x\ne0,x\ne27\right)\)
\(\Leftrightarrow\dfrac{6}{x}-\dfrac{24}{x-27}=0\)
\(\Leftrightarrow\dfrac{6\left(x-27\right)-24x}{x\left(x-27\right)}=0\)
\(\Leftrightarrow6x-162-24x=0\)
\(\Leftrightarrow-18x=162\)
\(\Leftrightarrow x=--9\)
`6/x = 24/(x-27)`
`=> 6 (x-27)= 24x`
`=> 6x - 162=24x`
`=> 6x - 24x=162`
`=>-18x=162`
`=>x=162 :(-18)`
`=>x=-9`
\(\dfrac{6}{x}=\dfrac{24}{x-27}\left(ĐKXĐ:x\ne0;x\ne27\right)\)
\(\Leftrightarrow\dfrac{6}{x}-\dfrac{24}{x-27}=0\)
\(\Leftrightarrow\dfrac{6\left(x-27\right)}{x\left(x-27\right)}-\dfrac{24x}{x\left(x-27\right)}=0\)
\(\Leftrightarrow\dfrac{6x-162}{x\left(x-27\right)}-\dfrac{24x}{x\left(x-27\right)}=0\)
\(\Leftrightarrow\dfrac{6x-162-24x}{x\left(x-27\right)}=0\)
\(\Rightarrow6x-162-24x=0\)
\(\Leftrightarrow-18x-162=0\)
\(\Leftrightarrow-18x=162\)
\(\Leftrightarrow x=-9\left(tm\right)\)
`a/b` vài `c/d`
hai phấn số này bằng nhau khi`
`axxc=bxxd`
\(\dfrac{6}{x}\) =\(\dfrac{24}{x-27}\)
6(x-27)=x.24
6x-162=24x
6x-24x=162
(-18)x=162
x=-9
