Giải :
a) X x ab = ab0ab
=> X = ab0ab : ab
=> X = ( ab000 + ab ) : ab
=> X = ab000 : ab + ab : ab
=> X = 1000 + 1 = 1001
Vậy X = 1001
b) abcabc : X = abc
=> X = abcabc : abc
=> X = ( abc000 + abc ) : abc
=> X = abc000 : abc + abc : abc
=> X = 1000 + 1 = 1001
Vậy X = 1001
Đáp án :
a) X = 1001
b) X = abcabc : abc
X = 101
a) \(x \)xab = ab0ab
\(x\) = ab0ab : ab
\(x \) = 1001
b)abcabc : x = abc
x = abcabc : abc
x = 1001
a) X = 1001
b) X = 101