Question

TÌM X, BIẾT :
a, \(\left(x+\frac{1}{3}\right)^3=\frac{-8}{27}\)

b, \(\left(\frac{1}{3}x+\frac{4}{3}\right)^2=\frac{25}{9}\)

c, \(2^x+2^{x+1}=24\)

- Cần gấp. Các bạn giả chi tiết dùm mình. Mình sẽ cho 3 tick. 17/7/2017 là mình phải có đáp án rồi. Cảm ơn.

Answer 1

a) \(\left(x+\frac{1}{3}\right)^3=\frac{-8}{27}\)

\(\left(x+\frac{1}{3}\right)^3=\left(\frac{-2}{3}\right)^3\)

\(x+\frac{1}{3}=\frac{-2}{3}\)

\(x=-1\)

b) \(\left(\frac{1}{3}x+\frac{4}{3}\right)^2=\frac{25}{9}\)

\(\left(\frac{1}{3}x+\frac{4}{3}\right)^2=\left(\frac{5}{3}\right)^2\)

\(\frac{1}{3}x+\frac{4}{3}=\frac{5}{3}\)

\(\frac{1}{3}x=\frac{1}{3}\)

\(x=1\)

c) \(2^x+2^{x+1}=24\)

\(2^x+2^x.2=24\)

\(2^x.\left(1+2\right)=24\)

\(2^x.3=24\)

\(2^x=8\)

\(2^x=2^3\)

\(x=3\)

Answer 2

a, (x+1/3)^3 = -8/27

=>(x+1/3)^3 = (-2/3)^3

=>x+1/3     = -2/3

=>x           = -1

b, (1/3x+4/3)^2 = 25/9

=>(1/3x+4/3)^2 = (5/3)^2

=>(1/3x+4/3)   = 5/3

=>1/3x           = 1/3

=>    x           = 1

c, 2^x + 2^x+1 = 24

=>2^x + 2^x . 2 = 24

=>2^x.(1+2)     = 24

=>2^x . 3         = 24

=>2^x              =8

=>2^x             = 2^3

=>  x              = 3

Answer 3

bn tk cho mình nha