Tìm x, biêt:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) \(172.x^2-7^9:98^3=2^{-3}\)
TÌm x
a)\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
b) 172 . x2 - 79 : 98 3 = 2 -3
Tìm x:
a)\(5^x.\left(5^3\right)^2=625\)
b)\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\)
c)\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d)\(172.x^2-7^9:98^3=2^{-3}\)
Tìm x biết :
\(172x^2-7^9:98^3=2^{-3}\)
\(\left(\frac{-3}{4}\right)^{3x-1}=\frac{256}{81}\)
tìm x biết:
a) \(5^x.\left(5^3\right)^2=625\)
b)\(\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{3}\right)^{-5}-\left(-\dfrac{3}{5}\right)^4\)
c)\(\left(-\dfrac{3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
d)\(172x^2-7^9:98^3=2^{-3}\)
tìm x:
\(a,5^x.\left(5^2\right)^3=625\)
\(b,\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{4}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
\(c,\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
\(d,172x^2-7^9:98^3=2^{-3}\)
bài 1: Tìm x,y biết rằng:
\(x+(-\frac{31}{12})^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x biết:
a.\(5^x.\left(5^3\right)^2=625\) b.\(\left(\frac{12}{25}\right)^x=\left(\frac{5}{3}\right)^{-2}-\left(-\frac{3}{5}\right)^4\) c.\(\left(-\frac{3}{4}\right)^{3x-1}=\frac{256}{81}\)
d.\(172x^2-7^9:98^3=2^{-3}\)
Bài 3: Tìm x \(\varepsilon\)N biết:
a.\(8< 2^x\le2^9\times2^{-5}\) b.\(27< 81^3:3^x< 243\) \(\left(\frac{2}{5}\right)^x>\left(\frac{5}{2}\right)^{-3}\times\left(-\frac{2}{5}\right)^2\)c.
a) \(\frac{\left(x+\frac{3}{4}\right)\cdot\frac{7}{2}-\frac{1}{6}}{-\left(\frac{4}{5}+\frac{1}{3}\right)\cdot\frac{1}{2}+1}=2\frac{33}{52}\)
b) \(\frac{\left(5-\frac{2}{7}\right)\cdot\frac{7}{9}:\frac{3}{5}}{\left(3x-\frac{5}{6}\right):\frac{1}{7}}=5\frac{5}{21}\)
Bài 7: Tìm x biết
CAC BAN GIUP MK NHA
AI CO CAU TRA LOI NHANH NHAT VA CHINH XAC NHAT THI MK TICK CHO
cho đa thức \(f\left(x\right)=4\cdot x^2+3x+1\); \(g\left(x\right)=3x^2-2x+1\); \(k\left(x\right)=7\cdot x^2-35x+42\)
a) tính f(x)-g(x)=h(x)
b) tính nghiệm của h(x) và k(x)
c) tìm gia trị của đa thức h(x) biết:
\(\left(x^2-9\right)^{2021}=\left(\frac{3}{4}-81\right)\cdot\left(\frac{3^2}{5}-81\right)^2\cdot\left(\frac{3^2}{6}-81\right)^3\cdot\cdot\cdot\left(\frac{3^{2020}}{2023}-81\right)^{2020}\)