Question

Tìm x biết :

a. 5 (x +35) = 515

b. 96 - 3(x + 1) = 49

c. 12x -33 =3².3³

Answer 1

a) 5 ( x + 35 ) = 515

         x + 35 = 103

         x         = 68

b) 96 - 3(x+1) = 49 

           3(x+1) = 47

              x + 1 = 47/3

              x = 44/3

c) 12x - 33 = 3^2 * 3^3

     12x - 33 = 243

      12x = 276

          x = 23

Answer 2

5 ( x + 35 ) = 515

     x + 35  = 515 : 5

      x + 35 = 103

      x        = 103 - 35

      x         = 68

96 - 3( x + 1 ) = 49

       3( x + 1 ) = 96 - 49

        3( x + 1 ) = 47

            x + 1   = 47/3

            x         = 47/3 - 1 

             x        = 44/3

12x - 33 = 3² . 3³

12x - 33 = 3⁵

12x - 33 = 243

12x        = 243 + 33

12x        = 276

    x       = 276 : 12

     x       = 23

Answer 3

\(a.5\cdot\left(x+35\right)=515\)         

\(x+35=515:5\)

\(x+35=103\)

\(x=103-35\)      

x=68

\(b.96-3\left(x+1\right)=49\)  

\(3\left(x+1\right)=96-49\)         

\(3\left(x+1\right)=47\)

\(x+1=\frac{47}{3}\) 

\(x=\frac{47}{3}-1\)

\(x=\frac{44}{3}\)

\(c.12x-33=3^2\cdot3^3\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=276:12\)

\(x=23\)

Answer 4

a. 5 (x +35) = 515

=>  (x +35) = 515 : 5

=>   x +35 = 103

=>   x        = 103 - 35

=>   x        =    68

b. 96 - 3(x + 1) = 49

=>       3(x + 1) = 96 - 49

=>       3(x + 1) = 47

=>         (x + 1) = 47 :3

=>          x + 1  = \(\frac{47}{3}\)

=>          x        = \(\frac{47}{3}\)- 1

=>         x        =      \(\frac{44}{3}\)

c. 12x -33 =3².3³

=> 12x - 33 = \(^{3^5}\)

=>  12x - 33 = 243

=>  12x        =  243 + 33

=>  12x        =      276

=>      x        =  276 : 12

=>      x        =     23