Question

Tìm x biết 

  a, 3/3 - ( x - 7/3 ) = [ -3/4 - 9/8]

  b, 3 - ( 8/3 - x + 5/4 ) =  1- [ 7/6 - 5/12 ]

Answer 1

a)   \(\frac{3}{3}-\left(x-\frac{7}{3}\right)=-\frac{3}{4}-\frac{9}{8}\)

\(1-\left(x-\frac{7}{3}\right)=-\frac{15}{8}\)

\(x-\frac{7}{3}=1--\frac{15}{8}\)

\(x-\frac{7}{3}=\frac{23}{8}\)

\(x=\frac{23}{8}+\frac{7}{3}=\frac{125}{24}\)

Answer 2

b) \(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=1-\left(\frac{7}{6}-\frac{5}{12}\right)\)

\(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=\frac{1}{4}\)

\(\frac{8}{3}-x+\frac{5}{4}=1-\frac{1}{4}\)

\(-x=1-\frac{1}{4}-\frac{8}{3}-\frac{5}{4}\)

\(-x=-\frac{19}{6}\)

\(\Rightarrow x=\frac{19}{6}\)

Answer 3

a) \(\frac{3}{3}-\left(x-\frac{7}{3}\right)=\left(\frac{-3}{4}-\frac{9}{8}\right)\)

\(1-x+\frac{7}{3}=\frac{-15}{8}\)

\(1+\frac{7}{3}-x=\frac{-15}{8}\)

\(\frac{10}{3}-x=\frac{-15}{8}\)

\(x=\frac{10}{3}-\left(\frac{-15}{8}\right)\)

\(x=\frac{125}{24}\)

b) \(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=1-\left(\frac{7}{6}-\frac{5}{12}\right)\)

\(3-\frac{8}{3}+x-\frac{5}{4}=1-\frac{3}{4}\)

\(\left(3-\frac{8}{3}-\frac{5}{4}\right)+x=\frac{1}{4}\)

\(\frac{-11}{12}+x=\frac{1}{4}\)

\(x=\frac{1}{4}-\left(\frac{-11}{12}\right)\)

\(x=\frac{-7}{6}\)