a) Ta có ( 2x - 3 )^2 = 16
=> ( 2x - 3 ) ^2 = 4^2
=> 2x - 3 = 4
=> 2x = 7
=> x = 7 / 2
bạn làm thiếu 1 bước ở phần a là : 2 x = 4 + 3
2x = 7
\(\left(2x-3\right)^2=16\)
\(\left(2x-3\right)^2=4^2\)
\(2x-3=4\)
\(2x=4+3=7\)
\(x=\frac{7}{2}\)
c)\(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\Rightarrow2^{-1}\cdot2^n+4\cdot2^n=8+1\cdot2^5\)
\(\Rightarrow1\cdot2^{n-1}+4\cdot2^n=\left(8+1\right)\cdot2^5\)
\(\Rightarrow2^{n-1}=2^5\)
\(\Rightarrow n-1=5\)
\(n=5+1=6\)