Th1: 9x+3=0
9x=-3
x= -1/3
Th2 : 2x-8=0
2x=8
x=4
\(\Rightarrow3\left(3x+1\right).2\left(x-4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=4\end{matrix}\right.\)
Tìm x biết 3 ( 2 x - 1 ) ( 3 x - 1 ) - ( 2 x - 3 ) ( 9 x - 1 ) = 0
Tìm x biết 3( 2x - 1 )( 3x - 1 ) - ( 2x - 3 )( 9x - 1 ) = 0
Tìm x, biết:
a. 3(2x - 1)(3x - 1) - (2x - 3)(9x - 1) = 0
b. (x - 3)(x - 5) + 3 (x - 1) = (x - 1)(x - 3)
c. (x - 1)(x - 2) - (x + 2)(x + 1) = 8
Tìm x biết
a) (x+2).(x+3) - (x-2).(x+5)=10
b) (3x+2). (2x+9) - (x+2). (8x+11)=(x+1).(3-2x)
c) 3.(2x-1).(3x-1)-(2x-3).(9x-1)=0
d) (5x-8).(4x-5)-(3x-4).(2x+12)=12
Tìm x biết
a) (x-3)^2 -4=0
b) ( 2x+3)^2 - (2x+1)(2x-1) =22
c) (4x+3)(4x-3) -(4x-5)^2 =16
d) x^3 -9x^2 +27x-27 =-8
e) (x+1)^3 - x^2(x+3) =2
Tìm x biết
a) 6x(3x+5)-2x(9x-2)=17
b) 2x(3x-1)-3x(2x+11)-70=0
c) 5x(2x-3)-4(8-3x)=2(3+5x)
Giải chi tiết giúp mình nhé!!!!
TÌM X BIẾT \(\frac{X-1}{X^2-9X+20}+\frac{2X-2}{X^2-6X+8}+\frac{3X-3}{X^2-X-2}+\frac{4X-4}{X^2+6X+5}=0\)
Tìm x biết:
1.4x(2x-1)+x(3-4x)-6=0
2.(x+2)(x+3)-(x-2)(x+5)=6
3.3(2x-1)(3x-1)-(2x-3)(9x-1)=0
