\(\frac{9+x}{13-x}=\frac{5}{6}\Rightarrow6\left(9+x\right)=5\left(13-x\right)\)
\(\Leftrightarrow11x=11\Leftrightarrow x=1\)
Ta có : \(\frac{9-x}{13-x}=\frac{5}{6}\)
\(\Leftrightarrow\left(9-x\right).6=5.\left(13-x\right)\)
\(\Leftrightarrow54-6x=65-5x\)
\(\Leftrightarrow6x-5x=54-65\)
\(\Leftrightarrow-1x=-11\)
\(\Leftrightarrow x=-11\)
Vậy x = -11
\(\frac{9+x}{13-x}=\frac{5}{6}\)
\(\Rightarrow\left(9-x\right).6=5.\left(13-x\right)\)
\(\Rightarrow54-6x=5\left(13-x\right)\)\(\Rightarrow5x-6x=54-65=-11\)
\(\Rightarrow x=-11\)
tại sao lại ra 54 và 65 vậy bạn
