\(\left(8-5x\right)\left(x+2\right)+4\left(x-2\right)\left(x+1\right)+2\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow8x+16-5x^2-10x+4x^2+4x-8x-8+2x^2-8=0\)
\(\Leftrightarrow x^2-6x=0\Leftrightarrow x\left(x-6\right)=0\Leftrightarrow\orbr{\begin{cases}x=0\\x-6=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=6\end{cases}}}\)
Vậy S = { 0, 6}
Tìm x biết ( 8 - 5x) ( x + 2 ) + 4 ( x - 2) ( x + 1) + 2 ( x - 2 ) ( x + 2 ) = 0
tìm x biết
( 8 - 5x ) ( x + 2 ) + 4 ( x - 2 ) ( x + 1 ) + 2( x - 2) ( x + 2 ) = 0
Tìm x,biết
a) ( x+2)×(x+3)-(x -2)×(x+5)=0
b) (2x+3)×(x-4)+(x-5)×(x-2)=(3x-5)×(x-4)
c) (8-5x)×(x+2)+4(x-2)×(x+1)+2(x-2)×(x+2)=0
d) (8x-3)×(3x+2)-(4x+7)×(x+4)=(2x+1)×(5x-1)-33
Tìm x biết
a, 2x^2 + 3 ( x - 1)(x + 1) = 5x ( x + 1)
b, (8 - 5x) (x + 2) + 4 ( x - 2) ( x + 1) + 2 ( x - 2) ( x + 2 ) = 0
Tìm x , biết
a)(x+2)(x-3)-(x-2)(x+5)=0
b)(2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c)(8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0
giúp mình với nhé
BT2: Tìm x 2, 3x(x-4)+2x-8=0 3, 4x(x-3)+x^2-9=0 4, x(x-1)-x^2+3x=0 5, x(2x-1)-2x^2+5x=16
Tìm x.
(8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0
Tìm x
(8-5x)(x+2)+4(x-2)(x+1)+2(x-2)(x+2)=0
4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Tìm x
a) (x+2)(x+3)-(x-2)(x+5)=0
b)(8-5x)(x+2)+4(x-2)(x+1)+2.(x-2).(x+2)=0
