7x+2+2.7x-1=345
=>7x-1(73+2)=345
=>7x-1=345:345=1
=>x-1=0
=>x=1
7^x-1 . 7^x+3 + 2. 7^x-1 = 345
7^x-1 .(7^x+3 + 2) =345
7^x-1. (7^x+3 + 2) = 7^x+3 -2
7^x-1 =(7^x+3 - 2) : (7^x+3 +2)
7^x-1 = 0
=> x-1 = 1
chắc chắn luôn
7x+2+2.7x-1=345
=>7x-1(73+2)=345
=>7x-1=345:345=1
=>x-1=0
=>x=1
7^x-1 . 7^x+3 + 2. 7^x-1 = 345
7^x-1 .(7^x+3 + 2) =345
7^x-1. (7^x+3 + 2) = 7^x+3 -2
7^x-1 =(7^x+3 - 2) : (7^x+3 +2)
7^x-1 = 0
=> x-1 = 1
chắc chắn luôn
Tìm x biết:
a) 7x+2 + 2.7x-1= 345
b) 2x+2 - 2x= 96
Cho đề bài
Tìm X
7^x+2+2.7^x-1=345
Ai biết xin giúp dùm
7 mũ x+2+2.7 mũ x-1=345
Bài 2:Tìm x biết :
a)\(2^{x+2}-2^x=96\) b) \(7^{x+2}+2.7^{x-1}=345\)
\(7^{x+2}+2.7^{x-1}=\frac{345}{7}\)
Tìm x
b)7x+2+2.7x-1=345
c)5x+5x+2=650
d)(2x-1)6=(2x-1)8
2.3x+3x-1=7.(32+2.62)
7x+22.7x-1=345
tìm các số nguyên n sao cho
\(\left(\frac{4}{9}\right)^n=\left(\frac{2}{3}\right)^5\)
Tìm X
\(7^{X+2}+2.7^{X-1}=345\)
Tìm x biết :
a)\(3^{-2}.3^2.27^x=\frac{1}{3}\)
b)\(7^{x+2}+2.7^{x-1}=345\)
c)\(\left(2x-1\right)^6=\left(2x-1\right)^8\)