Lời giải:
$(6x)^3:8=(2x-1)^3$
$\Rightarrow (\frac{6x}{2})^3=(2x-1)^3$
$\Rightarrow (3x)^3=(2x-1)^3$
$\Rightarrow 3x=2x-1$
$\Rightarrow x=-1$
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Các câu hỏi tương tự
Tim so nguyen x biet : -x/2+2x/3+x+1/4+2x+1/6=3/8
Tim x biet:
a,[3x-4]=x
b,[x+8]=-3.x
c,[5x-3] = 2x+1
tim x biet
X+35=-22-X
(6X-4^2) .7^8=2.7^9
5.3^x-1-7.3^12=8.3^12
3.(x-15)^3=-24
lx+18l=10
Bai 1. 12 chia het ( x + 3 )
bai 2. Tim so tu nhien x, biet 6x + 4 chia het cho 2x
cac ban nho giai chi tiet giup minh nha cam on
lxl<6
5<x<11
tim x biet
5x+15=0
1-2x=37
x+35=-22-x
( 6x-4^2).7^8=2x7^9
tim x,y thuoc Z biet
|y|.|2x+3|=8
|2x+4|+|y-3|=0
|x-1|+|2y+7|=3
|x+5|+|2y+6| nho hon hoac bang 0
tim x
-2x(6x-2)+3x(4x-7)=8
(7x-2)(2x+3)-(3x-5)(4x+6)=2x2-5
+(-2x+3)-6x(3x-4)=-22x2+7x
Tim x biet
2x + 3 =7
x^2 +4 =8
tim x biet: ||x-1/2|.|2x-3/4||=2x-3/4