Question

Tìm x biết

 \(5^{x+2}\)= 125        \(6^x\).36 = 7776       \(x^2\). \(x^3\)= 243            \(x^8\)= \(x^3\)       

Answer 1

`a, 5^(x+2) = 125`

`-> x + 2 = 3`

`-> x = 1`

`b, -> 6^(x+2) = 6^5`

`-> x+2=5`

`-> x = 3`

`c, -> x^5 = 3^5`

`-> x = 3`

`d, -> x^3(x^5-1) = 0`

`->` \(\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Answer 2

\(5^{x+2}=125=>x+2=3=>x=1\) 

\(6^x.36=7776=>6^x=216=>x=3\)

\(x^2.x^3=243=>x^5=243=>x=3\)

\(x^8=x^3=>x\) thuoc {0;1)