\(5x=10\sqrt{x}\)
\(\Leftrightarrow5x=10\cdot x^{\frac{1}{2}}\)
\(\Leftrightarrow x=2\cdot x^{\frac{1}{2}}\)
\(\Leftrightarrow x^{\frac{1}{2}}=2\)
\(\Leftrightarrow\sqrt{x}=2\)
\(\Leftrightarrow\sqrt{x^2}=2^2\)
\(\Leftrightarrow x=4\)
Vậy x=4.
\(5x=10\sqrt{x}\)
\(\Rightarrow5\left(\sqrt{x}\right)^2=5.2\sqrt{x}\)
\(\Rightarrow\left(\sqrt{x}\right)^2=2\sqrt{x}\)
\(\Rightarrow\left(\sqrt{x}\right)^2-2\sqrt{x}=0\)
\(\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\sqrt{x}=0\\\sqrt{x}-2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\\sqrt{x}=2\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=4\end{cases}}}\)
Vậy \(\orbr{\begin{cases}x=0\\x=4\end{cases}}\)
