Ta có:
\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}\)
\(=1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{5x+1}-\frac{1}{5x+6}\)
\(=1-\frac{1}{5x+6}\)
\(=\frac{5x+5}{5x+6}=\frac{2010}{2011}\)
\(\Rightarrow5x+5=2010\)
\(\Rightarrow5x=2010-5=2005\)
\(\Rightarrow x=2005:5=401\)
Vậy x=401
tìm các số nguyên x thoả mãn:
5/1.6+5/6.11+...+5/(5x+1)(5x+6)=2010/2011
tìm x biết
5/1.6 + 5/6.11 + 5/11.16 + .... + 5/5x+1.5x+6 = 2010/2011
giải cụ thể nha
tìm x,y thỏa mãn
a.\(\frac{5}{1.6}+\frac{5}{6.11}+...+\frac{5}{\left(5x+1\right).\left(5x+6\right)}=\frac{2010}{2011}\)
Tìm số tự nhiên x thỏa mãn:
a) 5/1.6 + 5/6.11 +...+ 5/(5x + 1).(5x + 6) = 2010/2011
b) 1/3.5 + 1/5.7 + 1/7.9 +...+ 1/(2x + 1).(2x + 3) = 15/93
Tìm số tự nhiên x thỏa mãn: 5/1.6 + 5/6.11 +...+ 5/(5x+1).(5x+6) =2010/2011. b) 1/3.5+1/5.7+.,.+ 1/(2x+1).(2x+3) =15/93.
Tim x thuoc N biet 5/ 1.6 +5/ 6.11+....+5/ (5x+1).(5x+6)=2005/2006
tìm x
d) \(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{\left(5x+1\right)\left(5x+6\right)}=\frac{2005}{2006}\)
Timx
5/1.6+5/6.11+.........+5/(5x+1).(5x+6)=2005/2006
\(\frac{5}{1.6}+\frac{5}{6.11}+..+\frac{5}{\left(5x+1\right).\left(5x+6\right)}=\frac{2005}{2006}\)
