\(\text{Ta có: }\) \(50\%x+\frac{2}{3}x=x+4\)
\(\Leftrightarrow\frac{1}{2}x+\frac{2}{3}x=x+4\)
\(\Leftrightarrow x\left(\frac{1}{2}+\frac{2}{3}\right)=x+4\)
\(\Rightarrow\frac{7}{6}x=x+4\)
50%x + 2/3x = x+4
1/2x + 2/3x = x+4
(1/2 + 2/3)x = x+4
7/6x = x+4
7/6x-x =4
(7/6-1)x =4
1/6x=4
x=24
\(\frac{1}{2}\)x + \(\frac{2}{3}\)x =x+4
7/6x=x+4
1/6x +x=x+4
1/6x =4
x=4:1/6
x=24
Ta có: 50%x+
2
3 x=x+4
⇔
1
2 x+
2
3 x=x+4
⇔x(
1
2 +
2
3 )=x+4
⇒
7
6 x=x+
\(50\%x+\frac{2}{3}x=x+4\)
\(=>\frac{1}{2}x+\frac{2}{3}x=x+4\)
\(=>x\left(\frac{1}{2}+\frac{2}{3}\right)=x+4\)
\(=>\frac{7}{6}x=x+4\)
\(=>\frac{7}{6}x-x=4\)
\(=>\frac{1}{6}x=4\)
\(=>x=24\)
50%x + 2/3x = x+4
1/2x + 2/3x = x+4
(1/2 + 2/3)x = x+4
7/6x = x+4
7/6x-x =4
(7/6-1)x =4
1/6x=4
x=24