Question

tìm X biết \(42-\left(2x+32\right)+12:2=6\)

Answer 1

42 - (2x + 32 )+12:2=6

42 -(2x + 32)+6=6

42-(2x +32)=6-6

42-(2x+32)=0

42-2x=0+32

42-2x=32

2x=42-32

2x=10

x=10:2

x=5

Answer 2

42-(2x+32)+12:2=6

42-(2x+32)+12=6.2=12

42-(2x+32)=12-12

42-(2x+32)=0

2x+32=0+42=42

2x=42-32

2x=10

x=10:2

x=5

Answer 3

128-3(×+4)=23