(3x-1)2-9.(x+2)2=13
<=>(9x2-6x+1)-9.(x2+4x+4)=13
<=>9x2-6x+1-9x2-36x-36=13
<=>-42x-35=13
<=>-42x=13+35
<=>-42x=48
<=>x=-8/7
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(3x-1)2-9.(x+2)2=13
<=>(9x2-6x+1)-9.(x2+4x+4)=13
<=>9x2-6x+1-9x2-36x-36=13
<=>-42x-35=13
<=>-42x=13+35
<=>-42x=48
<=>x=-8/7
tim x biet (x^2+2x+1)(x+2)-x^2(x-3)-7x(x-1)=3x-9
tim x biet (x-2)^3 -(x-3)(x^2+3x+9)+6(x+1)^2
ai giup minh vs
tim x biet
(3x+2)(2x+9)-(x+2)(6x+1)=x+1-(x-9)
giup voi
tim x biet
2/3x^2-5x+2 + 13/3x^2+x+2 = 6/x
Tim x, biet:
a)(x-3)^3-(x-3)(x^2+3x+9)+9(x-1)^2=15
b)(x^2-2)^2+4(x-1)^2-4(x^2-2)(x-1)=0
Giup minh voi!
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
(tim x biet (x+1)(2-x)-(3x+5)(x+2)=-4x^2+1
tim x biet x^3-3x^2+3x-1=0
tim a b biet x ^4-3x +2=(x-1)(x^3+ax^2+bx-2)