2x(x - 1/7) = 0
=> 2x = 0 hoặc x - 1/7 = 0
=> x = 0 hoặc x = 1/7
Đúng cho mình nha
\(2x.\left(x-\frac{1}{7}\right)=0\)
\(\Leftrightarrow2x=0\) hoặc \(x-\frac{1}{7}=0\)
\(\Leftrightarrow x=0\) hoặc \(x=\frac{1}{7}\)
2x(x - 1/7) = 0
=> 2x = 0 hoặc x - 1/7 = 0
=> x = 0 hoặc x = 1/7
Đúng cho mình nha
\(2x.\left(x-\frac{1}{7}\right)=0\)
\(\Leftrightarrow2x=0\) hoặc \(x-\frac{1}{7}=0\)
\(\Leftrightarrow x=0\) hoặc \(x=\frac{1}{7}\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Tìm x biết :\(a,2x.\left(x-\frac{1}{7}\right)=0\)
b, \(\frac{2}{3}.\left(\frac{2}{5}+x\right)=\frac{2}{15}\)
1. Tìm x ϵ Q sao cho:
a) (2x-3). (x+1) < 0.
b) \(\left(x-\frac{1}{2}\right).\left(x+3\right)>0\)
2.Tính:
S=\(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{999.1001}\)
3.Tìm x: Biết x không thuộc{-2; -5; -10; -17}
\(\frac{3}{\left(x+2\right).\left(x+5\right)}+\frac{5}{\left(x+5\right).\left(x+10\right)}+\frac{7}{\left(x+10\right).\left(x+17\right)}=\frac{x}{\left(x+2\right).\left(x+17\right)}\)
Tìm x biết :
a) \(\frac{32-x}{7}=\frac{x-42}{9}\)
b) \(\left(2x-1\right)^2+\left|x+3\right|=0\)
Tìm x, biết:
a)\(\left(x+5\right).\left(x+9\right)>0\)
b)\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(-\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
TÌM X
a,\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=6\)
b,\(\left(x^2-4\right).\left(2x+\frac{4}{3}\right)=0\)
Tìm x biết : \(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(\frac{-1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
Tìm x biết:
a) x. \(\frac{1}{2}.\frac{2}{3}=4\)
b) \(\frac{-2}{7}.\frac{5}{7}.x=\frac{7}{21}\)
c) \(\left(x-\frac{1}{2}\right).\left(2x-\frac{1}{3}\right)=0\)
d) \(\frac{x+1}{3}+\frac{x+1}{4}+\frac{x+1}{5}=0\)
Tìm x biết :
a) \(\left|3x-2\right|=\left|3-2x\right|\)
b) \(\left|x+\frac{3}{5}\right|-\left|x-\frac{7}{3}\right|=0\)