Question

Tìm x biết : 2x^3 + 3x^2 + 2x + 3 = 0

 

Ai làm nhanh và đúng m tick cho....

Answer 1

x²(2x+3)+(2x+3)=0
(2x+3)(x²+1)=0
2x+3=0
x=-3/2

Answer 2

\(2x^3+3x^2+2x+3=0\)

\(\Leftrightarrow2x^3+2x+3x^2+3=0\)

\(\Leftrightarrow2x\left(x^2+1\right)+3\left(x^2+1\right)=0\)

\(\Leftrightarrow\left(2x+3\right)\left(x^2+1\right)=0\) vì \(x^2+1>0\) nên \(2x+3=0\Rightarrow x=-\frac{3}{2}\)

Answer 3

\(2x^3+3x^2+2x+3=0\)

\(x^2\left(2x+3\right)+\left(2x+3\right)=0\)

\(\left(x^2+1\right)\left(2x+3\right)=0\)

\(\Leftrightarrow2x+3=0\)( Vì \(x^2\ge0\forall x\Rightarrow x^2+1>0\forall x\))

\(x=-\frac{3}{2}\)

Vậy ...

Answer 4

2x³ + 3x² + 2x + 3 = 0

<=> (2x + 3)(x² + 1) = 0

<=> (2x + 3) = 0

<=> 2x = 0 - 3

<=> 2x = -3

<=> 2x/2 = -3/2

<=> x = -3/2

=> x = -3/2

Answer 5

<=> 2x³+2x+3x²+3=0

<=> 2x(x²+1)+3(x²​+1)=0

<=>(x²​+1)(2x+3)=0

<=> x²+1=0( vô lí vì x² >= 0, 1 > 0)

       2x+3=0 <=> x = -3/2 

Vậy nghiệm của phuơng trình là x = -3/2

Answer 6

\(2x^3+3x^2+2x+3=0\)

\(=\left(2x^3+2x\right)+\left(3x^2+3\right)=0\)

\(=2x\left(x^2+1\right)+3\left(x^2+1\right)=0\)

\(=\left(x^2+1\right)\left(2x+3\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\2x+3=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{-3}{2}\end{cases}}}\)

HOk Tốt!!!

Answer 7

\(2x^3+3x^2+2x+3=0\)

\(\Rightarrow2x\left(x^2+1\right)+3x\left(x^2+1\right)=0\)

\(\Rightarrow\left(x^2+1\right)\left(2x+3x\right)=0\)\

\(\Rightarrow\orbr{\begin{cases}x^2+1=0\left(loại\right)\\2x+3x=0\Rightarrow x=-5\end{cases}}\)