Ta có : |2x-1|+|1-2x|=8
=> |2x-1|+|2x-1|=8
=>2|2x-1|=8
=>|2x-1|=4
=>\(2x-1=\pm4\)
=>\(\orbr{\begin{cases}x=2,5\\x=-1,5\end{cases}}\)
Vậy x=2,5 hoặc x= -1,5
Ta có : |2x - 1| + |1 - 2x| = 8
<=> |2x - 1| + |2x - 1| = 8
=> 2.|2x - 1| = 8
=> |2x - 1| = 4
=> \(\orbr{\begin{cases}2x-1=4\\2x-1=-4\end{cases}\Rightarrow\orbr{\begin{cases}2x=5\\2x=-3\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{5}{2}\\x=-\frac{3}{2}\end{cases}}}\)