cái đề => 2.3^x.3^2 + 4.3^x.3 = 10.3^6
=>18.3^x + 12.3^x = 10. 3^6
=> 30.3^x=10.3^6
=> 3^x=3^5
=>x=5
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tim x biet : \(2\cdot3^{x+2}+4\cdot3^{x+1}=10\cdot3^6\)
\(|x+\frac{2017}{2018}|+|2y-6,4|+|z-\frac{2^{19}\cdot3^9\cdot15.2^{18}\cdot9^4}{2^9\cdot3^5\cdot2^{10}\cdot12^{10}}|=0\)
Bài 1 .\(A=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^{9\cdot14^3}}\)
Bài 2 .\(\frac{37-x}{x+13}=\frac{3}{7}\)
Bài 3 . \(x=\frac{y}{2}=\frac{z}{3}và4x-3y+2z=36\)
Bài 4 . \(x:y:z=3:4:5và2x^2+2y^2-3z^2=-100\)AI LÀM ĐƯỢC THÌ GIÚP MÌNH VỚI NHA!
\(B=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{56^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(TínhA=\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
Tính A:\(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49^2}{\left(125\cdot7\right)^3+5^9\cdot14^3}\)
\(\frac{2^{12}\cdot3^5-4^6\cdot3^6}{2^{12}\cdot9^3+8^4\cdot3^3}\)
tim x,y: \(2^{x-1}\cdot3^y=12^x\)
thực hiện phép tính:
A = \(\frac{2^{12}\cdot3^5-4^6\cdot9^2}{\left(2^2\cdot3\right)^6+8^4\cdot3^5}-\frac{5^{10}\cdot7^3-25^5\cdot49}{\left(125\cdot7\right)^3+5^9\cdot14^3}^2\)