Ta có : 23x+2 =4x+5
=> 23x+2 =22x+5 => 3x+2=2x+5
=> 3x-2x=5-2
=> x=3
Vậy x=3
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Ta có : 23x+2 =4x+5
=> 23x+2 =22x+5 => 3x+2=2x+5
=> 3x-2x=5-2
=> x=3
Vậy x=3
tim x biet : 2^3x+2 = 4^x+5
Tim x biet: (3/4x+5)-(2/3x-4)-(1/6x+1)=(1/3+4)-(1/3x-3)
Tim x biet:
(3/4x + 5) - (2/3x - 4) - (1/6x + 1) = (1/3x + 4) - (1/3x - 3)
Tim x,biet: \(2^{3x+2}=4^{x+5}\)
tim x , biet :
1 ) 2017 - \ x - 2017 \ = x
2) -1/2 . ( 3x - 1 ) + 3/4 . ( 3-2x) = -3 . ( x/2 - 1 ) - ( 4/5) mu -1
Tim x,y,z biet (x-1)/2= (y+3)/4 =(z-5)/6 va 5z-3x-4y
tim x biet
|x+1|+|3x+2|=3x
|x-2|+4|x+1|=x-3
Tim x biet
(X+1)×(x+2)<0 x-2/3x+2 <0
(-3+3/x -1/3) ÷ (1+2/3+2/5)=-5/4
Tim x biet
a) 3x+5-2(x+4)=4x+1/2b)(x+1)(x-1) <0c)(x-2)(x+2/3) >0