Các câu hỏi tương tự
tim x biet 1/x+1/x+2 + 1/x+5 +1/x+7= 1/x+1 +1/x+3 +1/x+4 +1/x+6
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
tim x biet
\(6(x+1)^2-2(x+1)^3+2(x-1)(x^2+x+1)=1\)
Tim x x(x+5)(x-5) - (x+2)(x^2-2x+4)=5
(x+1)^3 - (x-1)^3 -6(x-1)^2 = -19
14 tháng 3 2022 lúc 10:06
1) (3x-2)/3-2=(4x+1)/42) (x-3)/4+(2x-1)/3=(2-x)/63) 1/2 (x+1)+1/4 (x+3)=3-1/3 (x+2)4) (x+4)/5-x+4=x/3-(x-2)/25) (4-5x)/6=2(-x+1)/2 6) (-(x-3))/2-2=5(x+2)/4 7)2(2x+1)/5-(6+x)/3=(5-4x)/158) (7-3x)/2-(5+x)/5=1 9)(x-1)/2+3(x+1)/8=(11-5x)/310)(3+5x)/5-3=(9x-3)/4
tim x bieta/(3x-5)(2x-1)-(x+2)(6x-1)0b/ (3x-5)(3x+2)-(3x-1)2-5c/(3x+2)(x-5)3(x-1)2-2d/ (x+1)2/3 - (x-2)2/2 2x+1/2 (x-3)2/6g/49x2(3x+2)2h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)0i/ (x-2)(x2-2x+4)-x(x2+2)15k/ 6x2-7x-30m/(x+5)(x-3)+x2-250e/ x3+3x24x+12f/ (6x+7)2(3x+4)(x+1)6
Đọc tiếp
tim x biet
a/(3x-5)(2x-1)-(x+2)(6x-1)=0
b/ (3x-5)(3x+2)-(3x-1)2=-5
c/(3x+2)(x-5)=3(x-1)2-2
d/ (x+1)2/3 - (x-2)2/2 = 2x+1/2 (x-3)2/6
g/49x2=(3x+2)2
h/(3x-4)2-(2x-2)2-3(x-2)(2x-1)=0
i/ (x-2)(x2-2x+4)-x(x2+2)=15
k/ 6x2-7x-3=0
m/(x+5)(x-3)+x2-25=0
e/ x3+3x2=4x+12
f/ (6x+7)2(3x+4)(x+1)=6
tim x
1) 4x(x-5)-(x-1)(4x-3)=5
2) (x-5)(x-4)-(x+1)(x-2)=7
3) (x-5)(-x+4)-(x-1)(x+3)=-2x2
tim m biet
a) (x^2-x+1)x-(x+1)x^2+m= -2x^2+x+5
b) -x^2(x^2+x+1+2)= -x^4-x^3-x^2+m
giup vs nhanh mk dag can gap
1.giải các phương trình sau:
a, 3(2x+1)/4 - 5x+3/6 = 2x-1/3 - 3-x/4
b, 19/4 - 2(3x-5)/5 = 3-2x/10 - 3x-1/4
c, x-2*3/2+3 + x-3*5/3+5 + x-5*2/5+2 = 10
d, x-3/5*7 + x-5/3*7 + x-7/3*5 = 2(1/3 + 1/5 + 1/7)
2. giải các phương trình:
a, x-1/9 + x-2/8 = x-3/7 + x-4/6
b, (1/1*2 + 1/2*3 + 1/3*4 + ... + 1/9*10) (x-1) + 1/10x = x- 9/10