\(\frac{\left(15+x\right)}{37}=\frac{54}{14}\)
\(\Rightarrow\) \(\left(15+x\right)×14=37×54\)
\(\left(15+x\right)×14=1998\)
\(15+x=1998\div14\)
\(15+x=\frac{999}{7}\)
\(x=\frac{999}{7}-15\)
\(x=\frac{999}{7}-\frac{105}{7}\)
\(x=\frac{894}{7}\)
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