`1/14x+5/7=-3/2`
`=>1/14x=-3/2-5/7`
`=>1/14x=-21/14-10/14`
`=>1/14x=-31/14`
`=>x=-31/14 : 1/14`
`=>x=-31/14 . 14`
`=>x=-31`
Vậy `x=-31`
`#QiN`
\(\dfrac{1}{14}x+\dfrac{5}{7}=-\dfrac{3}{2}\) (đề ntn phải ko ạ?)
`=> 1/14x=-3/2-5/7`
`=>1/14x=-31/14`
`=>x=-31/14:1/14`
`=>x=-31`