Đặt \(A=\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{\left(3x-2\right).\left(3x+1\right)}\)
\(3A=\frac{3}{1.4}+\frac{3}{4.7}+...+\frac{3}{\left(3x-2\right)\left(3x+1\right)}\)
\(3A=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{\left(3x-2\right)}-\frac{1}{\left(3x+1\right)}\)
\(3A=1-\frac{1}{3x+1}\)
\(A=\left(1-\frac{1}{3x+1}\right).\frac{1}{3}\)
bài này tính tổng hứ làm sao tìm dc x