|1 -1/2:x|= |-1/2|
|1-1/2:x| = 1/2
1-1/2:x = 1/2 hay 1-1/2:x=-1/2
1/2:x= 1- 1/2 hay 1/2:x = 1+1/2
1/2:x = 1/2 hay 1/2:x = 3/2
x= 1/2:1/2 hay x= 1/2: 3/2
x= 1 hay x= 1/3
|1 -1/2:x|= |-1/2|
|1-1/2:x| = 1/2
1-1/2:x = 1/2 hay 1-1/2:x=-1/2
1/2:x= 1- 1/2 hay 1/2:x = 1+1/2
1/2:x = 1/2 hay 1/2:x = 3/2
x= 1/2:1/2 hay x= 1/2: 3/2
x= 1 hay x= 1/3
Tìm x biết \(\frac{x+1}{2}+\frac{x+1}{2}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
1,Tìm số hữu tỉ x biết\(\frac{x+4}{2005}+\frac{x+3}{2006}=\frac{x+2}{2007}+\frac{x+1}{2008}\)
2,tìm x biết:\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)
Tìm x biết:
1) \(\frac{x+1}{2}+\frac{x+1}{3}+\frac{x+1}{4}=\frac{x+1}{5}+\frac{x+1}{6}\)
2) \(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
Tìm x, biết:
\(3-\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
Tìm x biết : \(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2004}\right)x=\frac{2013}{1}+\frac{2012}{2}+...+\frac{2}{2012}+\frac{1}{2013}\)
Bài 2
a) Tìm x biết\(\frac{1}{2}-\left|\frac{5}{4}-2x\right|=\frac{1}{3}\)
b) Tìm x biết \(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c) Tìm ba số x, y, z thỏa mãn: \(\frac{x}{y}=\frac{10}{9};\frac{y}{z}=\frac{3}{4}\)và \(x-y+z=78\)
CMR: \(\frac{1}{2^2}-\frac{1}{2^4}+\frac{1}{2^6}-...+\frac{1}{2^{2002}}-\frac{1}{2^{2004}}< 0,2\)
tìm x biết:
\(|x-\frac{1}{3}|=|\left(-3,2\right)+\frac{2}{5}|\)
\(\frac{x-1}{2011}+\frac{x-2}{2010}-\frac{x-3}{2009}=\frac{x-4}{2008}\)
tìm x biết
\([\frac{1}{2}x^2(2x-1)^m-\frac{1}{2}x^{m+2}]:\frac{1}{2}x^2=0\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right).x=\frac{2013}{1}+\frac{2012}{2}+...+\frac{2}{2012}+\frac{1}{2013}\)Tìm x biết: