\(3^{2x-1}=3^8:3\)
\(3^{2x-1}=3^7\)
\(\Leftrightarrow2x-1=7\)
\(2x=8\)
\(x=4\)
\(3^{2x-1}=3^8:3\)
\(\Rightarrow3^{2x-1}=3^7\)
\(\Rightarrow2x-1=7\)
\(\Rightarrow\)2x= 8
\(\Rightarrow\)x=4
vậy x=4
32x-1 = 38 : 3
32x-1 = 37
2x - 1 = 7
2x = 7 + 1
x = 8 : 2
x = 4
\(3^{2x-1}=3^8:3\)
\(\Rightarrow3^{2x-1}=3^7\)
\(\Rightarrow2x-1=7\)
\(\Rightarrow2x=7+1\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=8:2\)
\(\Rightarrow x=4\)
Vậy x = 4
_Chúc bạn học tốt_
Ta có : \(3^{2x-1}=3^8:3\)
\(\Leftrightarrow3^{2x-1}=3^7\)
<=> 2x - 1 = 7
<= >2x = 8
<=> x = 4
Vậy x = 4
32x-1 = 38 : 3
32x-1 = 37
2x - 1 = 7
2x = 7 + 1
x = 8 : 2
x = 4
hok tốt