lx-2l+3l2-xl+l4x-8l=32
=>lx-2l+3l2-xl+4lx-2l=32
=>lx-2l(1+3+4)=32
=>lx-2l=32:8
=>lx-2l=4
=>x-2=-4;4
=>x=-2;6
Vậy x=-2;6
|x - 2| + 3|2 - x| + |4x - 8| = 32
|x - 2| + 3|x - 2| + 4|x - 2| = 32
(1 + 3 + 4) . |x - 2| = 32
8|x - 2| = 32
|x - 2| = 32 : 8
|x - 2| = 4
TH1: x - 2 = 4 => x = 6
TH2: x - 2 = -4 => x = -2
Vậy x thuộc {-2 ; 6}