câu a)x3-2.x2=0
=>x2.(x-2)=0
=>x2=0 hoặc x-2=0
=>x thuộc{0;2}
Vậy x thuộc{0;2}
Câu b)311-x+82=46+(x-21)-3x
=>393-x=25-2x
=>393-x=25-x-x
=>393=25-x
=>x=-368
Vậy x= -368
311-x+82=46+(x-21). Tìm x
1,tìm x
a,311-x+82=46=(x-21)
b,/3x-15/=0
c,/x+9/=12
giúp mk vs m.n
Tìm x :
a/ x3 - 2 . x2 = 0
b/ 311 - x + 82 = 46 + ( x - 21 ) - 3x
311-x+82=46+(x-21)
311 - x + 82 = 46 + ( x - 21 )
Tìm x
a,-18 - x = ( -8 ) + ( -13)
b,-x+(-32)+(-46)=(-84)
c,x-43=(57-x)-50
d,311-x + 82 = 46 + ( x - 21 )
e, 3x + 82 = -8
f, /x/ + 2 = 7
g, / 2x -15 / = 5
h, x = ( 2+x ) - x ( x+3 ) = 11
l, -4 ( 2x + 9 ) - ( -8x + 3 ) - ( x + 13 ) = 0
Giúp mk vs ah
tìm x ho mình với( mỗi caai 2 tích , trình bày đầy đủ)
a) 311-x+82=46+(x-21)
b) -(x-3+85)=(x+70-71)-5
c)(-x+821+534)=499+(x-84)
d)x+96=(443-x)-447
e)(x-12)-15)=(20-7)-(18+x)
311-x+82=46+x-21
-(x-3+84)=-x+70-71-5
tim so nguyen x
a,311-x+82=46+(x-21)
b,-(x-3+85)=(x+70-71)-5
