a) (x + 5/6) . 12/5 - 5/4 = 35%
=> (x + 5/6) . 12/5 = 7/20 + 5/4
=> (x + 5/6) . 12/5 = 8/5
=> x + 5/6 = 8/5 : 12/5
=> x + 5/6 = 2/3
=> x = 2/3 - 5/6
=> x = -1/6
b) 3.(x - 1/2) - 5.(x + 3/5) = -x + 1/5
=> 3x - 3/2 - 5x - 3 = -x + 1/5
=> -2x - 9/2 = -x + 1/5
=> -2x + x = 1/5 + 9/2
=> -x = 47/10
=> x = -47/10
c) 5/2 - 3.(1/3 - x) = 1/4 - 7x
=> 5/2 - 1 + 3x = 1/4 - 7x
=> 3/2 + 3x = 1/4 - 7x
=> 3/x + 7x = 1/4 - 3/2
=> 10x = -5/4
=> x = -5/4 : 10
=> x = -1/8
d) 1/2x + 4/5 .(5/2 + x) = 15/4
=> 1/2x + 2 + 4/5x = 15/4
=> 13/10x = 15/4 - 2
=> 13/10x = 7/4
=> x = 7/4 : 13/10
=> x= 35/26
a. \(\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=\frac{35}{100}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=\frac{7}{20}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{7}{20}+\frac{5}{4}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{7}{20}+\frac{25}{20}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{32}{20}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{8}{5}\)
\(x+\frac{5}{6}=\frac{8}{5}:\frac{12}{5}\)
\(x+\frac{5}{6}=\frac{8}{5}.\frac{5}{12}\)
\(x+\frac{5}{6}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{5}{6}\)
\(x=\frac{4}{6}-\frac{5}{6}\)
\(x=\frac{-1}{6}\)
b. \(3.\left(x-\frac{1}{2}\right)-5.\left(x+\frac{3}{5}\right)=-x\) \(+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x+3=-x+\frac{1}{5}\)
\(\left(3-5\right)x-\frac{3}{2}-3=-x+\frac{1}{5}\)
\(-2x+x-\frac{3}{2}=\frac{1}{5}+3\)
\(\left(-2+1\right)x-\frac{3}{2}=\frac{16}{5}\)
\(-1x=\frac{16}{5}+\frac{3}{2}\)
\(-1x=\frac{47}{10}\)
\(x=-\frac{47}{10}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=35\%\)
\(\Rightarrow\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=\frac{7}{20}\)
\(\Rightarrow\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{7}{20}+\frac{5}{4}\)
\(\Rightarrow\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{8}{5}\)
\(\Rightarrow x+\frac{5}{6}=\frac{8}{5}:\frac{12}{5}\)
\(\Rightarrow x+\frac{5}{6}=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}-\frac{5}{6}\)
\(\Rightarrow x=\frac{-1}{6}\)
~ Hok tốt ~
\(\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=35\%\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}-\frac{5}{4}=\frac{7}{20}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{7}{20}+\frac{5}{4}\)
\(\left(x+\frac{5}{6}\right).\frac{12}{5}=\frac{8}{5}\)
\(\left(x+\frac{5}{6}\right)=\frac{8}{5}:\frac{12}{5}\)
\(x+\frac{5}{6}=\frac{2}{3}\)
\(x=\frac{2}{3}-\frac{5}{6}\)
\(x=-\frac{1}{6}\)
Vậy \(x=-\frac{1}{6}\)