a) ( x - 15 ) . 35 = 0
x - 15 = 0 : 35
x - 15 = 0
x = 0 + 15
x = 15
b) 32 ( x - 10 ) = 32
x - 10 = 32 : 32
x - 10 = 1
x = 1 + 10
x = 11
a) (x - 15) . 35 = 0
(x - 15)=0 : 35
(x - 15)=0
x=0+15
x=15
b) 32.(x - 10) = 32
(x - 10) = 32 : 32
(x - 10) = 1
x = 1 + 10
x = 11
a. (x-15).35=0
=> x-15=0:35
=> x-15=0
=>x=0+15
=>x=15
vậy x=15
b) 32. (x-10)=32
=> x-10=32:32
=>x-10=1
=>x=1+10
=>x=11
vậy x=11
a)(x-15).35=0
x-15=0:35
x-15=0
x. =0+15
x =15
Vậy x=15
b)32.(x-10)=32
x-10. =32:32
x-10=1
x. =1+10
x=11
Vậy x=11😉
Tìm x :
a) ( x - 15 ) . 35 = 0
x - 15 = 0 : 35
x - 15 = 0
x = 0 + 15
x = 15
b) 32 ( x - 10 ) = 32
x - 10 = 32 : 32
x - 10 = 1
x = 1 + 10
x = 11
\(a,\left(x-15\right)\times35=0\)
\(\Rightarrow x-15=0\div35\)
\(\Rightarrow x-15=0\)
\(\Rightarrow x=0+15\)
\(\Rightarrow x=15\)
\(b,32\left(x-10\right)=32\)
\(\Rightarrow x-10=32\div32\)
\(\Rightarrow x-10=1\)
\(\Rightarrow x=1+10\)
\(\Rightarrow x=11\)
a,(x-15).35=0 b,32 (x-10)=32
x-15=0:35 x-10=32:32
x-15=0 x-10=1
x=0+15=15 x=1+10=11
Vậy x=15 Vậy x=11
k mình nha NGỌC nha nannanan
a) ( x - 15 ) . 35 = 0
=> x - 15 = 0
=> x = 15
Vậy x = 15
b) 32. ( x - 10 ) = 32
=> x - 10 = 1
=> x = 11
Vậy x = 11
a) ( x - 15 ) . 35 = 0
<=> x - 15 = 0
<=> x = 15
b) 32 ( x - 10 ) = 32
<=> x - 10 = 1
<=> x = 11
(X - 15) . 35 = 0
X - 15 = 0 : 35 = 0
x = 0 + 15
x = 15
32 (x - 10) = 32
x - 10 = 32 : 32 = 1
x = 1 + 10
x = 11
Học tốt!