a.Đkxđ:x khác 0
pt tương đương x^2=81 <=> x=9 hoặc x=-9
b.tương tự nhé
a.Đkxđ:x khác 0
pt tương đương x^2=81 <=> x=9 hoặc x=-9
b.tương tự nhé
Tìm x,y
a,\(\frac{x}{-15}=\frac{-60}{x}\)
b,\(\frac{x}{3}=\frac{y}{2}\)và\(2x+y=-32\)
c,\(\left(x+\frac{2}{3}\right)^3=\frac{27}{64}\)
d,\(6-|\frac{1}{2}-x|=\frac{2}{5}\)
tìm x biết : a,\(\frac{x}{-15}=\frac{-60}{x}\) ; b,\(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)
Tìm x, biết :
a) \(\frac{x-1}{27}=\frac{-3}{1-x}\)
b) \(\left(2\frac{1}{9}-\frac{15}{2135}:\frac{9}{4270}\right):x=\frac{222}{333}.\frac{2121}{4040}:\frac{132132}{660660}\)
tính
\(\frac{-1}{3}+\frac{0,2-0,3+\frac{5}{11}}{-0,3+\frac{9}{16}-\frac{15}{12}}\)
tìm x :
\(\frac{29-x}{21}+\frac{27-x}{23}+\frac{25-x}{25}+\frac{23-x}{27}+\frac{21-x}{29}=0\)
giúp mình nhé thanks
Tìm x , biết :
a. \(\frac{3}{-x}=\frac{-15}{81}\)
b.\(\frac{-x-7}{-22+1}=\frac{1}{5}\)
c.\(\frac{x^2}{5}=\frac{27}{15}\)
a) tìm x,y biết
\(\frac{x}{-3}=\frac{y}{5}\)và \(x\cdot y=-\frac{5}{27}\)
\(\frac{\frac{-1}{2}}{2x-1}=\frac{\frac{0.2}{-3}}{5}\)
b) Tìm x,y,z biết rằng \(\frac{1}{2}x=\frac{2}{3}y=\frac{3}{4}z\)và x - y = 15
Tìm x,y biết:
a.\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
b.\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)
Tìm x,y biết:
a)\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
b)\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)
Tìm x, biết
A.\(\left(-1\frac{1}{5}+x\right):\left(-3\frac{3}{5}\right)=-\frac{7}{4}+\frac{1}{4}:\frac{11}{8}\)
B.\(7,5x:\left(5\frac{195}{315}-8\right)=2\frac{13}{15}\)
C.\(60\%x+\frac{2}{3}x+x=688\)
D.\(1-\left(5\frac{3}{8}-x-7\frac{5}{24}\right):16\frac{2}{3}=0\)