a, \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
\(\left(\frac{2}{3}-\frac{3}{2}\right)x=\frac{5}{12}\)
\(\frac{-5}{6}x=\frac{5}{12}\)
x = \(\frac{-1}{2}\)
Vậy x = \(\frac{-1}{2}\)
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#Sunrise
a)2/3x-3/2x=5/12
x(2/3-3/2)=5/12
x(-5/6)=5/12
x=5/12/(-5/6)
x=-1/2
\(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)
\(\left|2x-\frac{1}{3}\right|=\frac{1}{6}\)
\(\Rightarrow\orbr{\begin{cases}2x-\frac{1}{3}=\frac{1}{6}\\2x-\frac{1}{3}=\frac{-1}{6}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=\frac{1}{2}\\2x=\frac{1}{6}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{4}\\x=\frac{1}{12}\end{cases}}\)
Vậy x \(\in\left\{\frac{1}{4};\frac{1}{12}\right\}\)
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#Sunrise
\(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
\(x\cdot\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\)
\(x\cdot\frac{-5}{6}=\frac{5}{12}\)
\(x=\frac{5}{12}\div\frac{-5}{6}\)
\(\Rightarrow x=\frac{-1}{2}\)
b) \(\frac{2}{5}+\frac{3}{5}\cdot\left(3x-3,7\right)=\frac{-53}{10}\)
\(1\cdot\left(3x-\frac{37}{10}\right)=\frac{-53}{10}\)
\(\left(3x-\frac{37}{10}\right)=\frac{-53}{10}\)
\(3x=\frac{-53}{10}+\frac{37}{10}\)
\(3x=\frac{-8}{5}\)
\(x=\frac{-8}{5}\div3\)
\(\Rightarrow x=\frac{-8}{15}\)
c) \(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{23}{27}-\frac{5}{9}\)
\(\frac{7}{9}\div\left(2+\frac{3}{4}x\right)=\frac{8}{27}\)
\(\left(2+\frac{3}{4}x\right)=\frac{7}{9}\div\frac{8}{27}\)
\(\left(2+\frac{3}{4}x\right)=\frac{21}{8}\)
\(\frac{3}{4}x=\frac{21}{8}-2\)
\(\frac{3}{4}x=\frac{5}{8}\)
\(x=\frac{5}{6}\)
d) \(|2x-\frac{1}{3}|+\frac{5}{6}=1\)
\(|2x-\frac{1}{3}|=1-\frac{5}{6}\)
\(|2x-\frac{1}{3}|=\frac{1}{6}\)
\(2x=\frac{1}{6}+\frac{1}{3}\)
\(2x=\frac{1}{2}\)
\(x=\frac{1}{2}\div2\)
\(\Rightarrow x=\frac{1}{4}\)
