tìm x trong các tỉ lệ thức sau :
\(a. \frac{x+5}{x+9}=\frac{x+4}{x+3}\)
\(b. \frac{2x-7}{2x+11}=\frac{5-3x}{4-2x}\)
\(c. \frac{3x+5}{-3x+11}=\frac{7x-5}{7-7x}\)
\(d. \frac{5x-3}{x+1}=\frac{5x-7}{x-1}\)
1,Tìm x:
a,3x-2=0
b,2x-1=0
c,5.(4+2x)=8+5x
d,\(\frac{1}{2}+\frac{3}{4}x=6-\frac{4}{5}x\)
e,3+2x=4-8x
f,\(5+\frac{1}{2}.\left(x+5\right)=3\)
tìm x\(\in\) Q,biết:
a,\(\frac{x}{2}\left(\frac{3x}{5}\right)-\frac{13}{5}=-\left(\frac{7}{5}+\frac{7}{10}x\right)\)
b,\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\)
c,\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\)
d,\(\frac{13}{x-1}+\frac{5}{2x+2}-\frac{6}{3x-3}\)
e,\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\left(2x-2\right)=\left(\frac{-3}{4}+\frac{5}{22}+\frac{3}{26}\right)\)
Ai bt câu nào làm câu đấy nhé ! Làm hết cũng đc nhé!
Dạng 5: Tìm x nguyên đểcác biểu thức sau có giá trị nguyên
a)\(A=\frac{3}{x-1}\)
b)\(B=\frac{x+2}{x+1}\)
c)\(C=\frac{5}{x}\)
d) \(D=\frac{11}{x+2}\)
Dạng 3: vận dụng các quy tắc: qt chuyển vế,qtdấu ngoặc, nhân phá ngoặc
a)3x –10 = 2x + 13
b) x + 12 = -5 –x
c) x + 5 = 10 –x
d)6x + 23= 2x –12
e) 12 –x = x + 1
f) 14 + 4x = 3x + 20
g) 2.(x-1) + 3(x-2) = x -4
h) 3.(4 –x) –2.( x-1) = x + 20
i) 4.( 2x + 7) –3.(3x –2) = 24
k) 3(x –2) + 2x = 10
a. 2.(\(\frac{1}{4}\)- 3x ) = \(\frac{1}{5}\)- 4x
b. \(\frac{2}{5}\)- 3 ( \(\frac{1}{3}\)- x ) = \(\frac{1}{4}\)- 7x
c. 5 | x - 3 | = \(\frac{5}{7}\)
d. -3 | 2x - 5 | = \(\frac{-3}{4}\)
e. \(\frac{1}{4}\). | 3x - 7 | = \(\frac{1}{5}\)
g. -\(\frac{7}{3}\). | -3x - \(\frac{1}{2}\)| = \(\frac{-7}{6}\)
1, Tìm x, biết
a, x-4>1,6
b, 2x-3>1,2
c, 7x-1>\(\frac{3}{4}\)
d, -5x+6<\(\frac{1}{3}\)
e, 7-8x>\(\frac{9}{16}\)
f, 2x-3>5x-4
2, Tìm x, biết
a,|x| +3=-19
b,|x| +\(\frac{1}{2}\)=\(3\frac{1}{2}\)
3, tìm x, biết
a, |3x-6|+4x+3=12
b, |6x-12|+3x-1=43
c, |8-4x|+7x-5=16-2x
CÁC BẠN LÀM NHANH GIÚP MK NHA
MK CẢM ƠN CÁC BẠN
Tìm số nguyên x biết
a,\(\frac{5}{6}\)=\(\frac{x-1}{x}\)
b,\(\frac{1}{2}\)=\(\frac{x+1}{3x}\)
c,\(\frac{3}{x+2}\)=\(\frac{5}{2x+1}\)
d,\(\frac{5}{8x-2}\)=\(\frac{-4}{7-x}\)
e,\(\frac{2x-1}{3}\)=\(\frac{3x+1}{4}\)
f,\(\frac{-3}{x+1}\)=\(\frac{4}{2-2x}\)
Giúp mik nha ^_^
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)
1 tìm x biết ;
a, 0-|x + 1| = 5
b, 2 - | \(\frac{3}{4}\)- x | = \(\frac{7}{12}\)
c, 2 | \(\frac{1}{2}\)x - \(\frac{1}{3}\)| - \(\frac{3}{2}\)= \(\frac{1}{4}\)
d, | x - \(\frac{1}{3}\)| = \(\frac{5}{6}\)
e, \(\frac{3}{4}\)- 2 | 2x - \(\frac{2}{3}\)| = 2
f, \(\frac{2x-1}{2}\)= \(\frac{5+3x}{3}\)