Question

Tim x :

A:   \(3\left(x+\frac{1}{2}\right)=8\)

B:  \(4x+\frac{1}{2}^3=-7\)

C:   \(4\left(x-\frac{1}{2}\right)+\left(-3\right)^2=9\)

GIUP HO MK NHE ..

Answer 1

a) \(3\left(x+\frac{1}{2}\right)=8\)

\(\Rightarrow x+\frac{1}{2}=\frac{8}{3}\)

\(\Rightarrow x=\frac{8}{3}-\frac{1}{2}\)

\(\Rightarrow x=\frac{13}{6}\)

b) \(4x+\frac{1}{2}^3=-7\)

\(\Rightarrow4x+\frac{1}{8}=-7\)

\(\Rightarrow4x=-7-\frac{1}{8}\)

\(\Rightarrow4x=-\frac{57}{8}\)

\(\Rightarrow x=-\frac{57}{8}:4\)

\(\Rightarrow x=\frac{1}{32}\)

c) \(4\left(x-\frac{1}{2}\right)+\left(-3\right)^2=9\)

\(\Rightarrow4\left(x-\frac{1}{2}\right)+9=9\)

\(\Rightarrow4\left(x-\frac{1}{2}\right)=0\)

\(\Rightarrow x-\frac{1}{2}=0\Rightarrow x=\frac{1}{2}\)

tíc mình nha

Answer 2

mk thay cau a co j khac y