a) \(\left(2x+3\right)^2=\frac{9}{21}\)
<=> \(\orbr{\begin{cases}2x+3=\frac{3}{11}\\2x+3=\frac{-3}{11}\end{cases}}\)
<=> \(\orbr{\begin{cases}x=-1\frac{4}{11}\\x=-1\frac{7}{11}\end{cases}}\)
Vậy...
b) \(\left(3x-1\right)^3=\frac{-8}{27}\)
<=> \(\left(3x-1\right)^3=\left(-\frac{2}{3}\right)^3\)
<=> \(3x-1=\frac{-2}{3}\)
<=> \(3x=\frac{1}{3}\)
<=> \(x=\frac{1}{9}\)
Vậy....