a)(2,8x-32):\(\frac{2}{3}\)=-90
2,8x-32=-90.\(\frac{2}{3}\)
2,8x =-60+32
x =-28:2,8
x=-10
b)(4,5-2x).1\(\frac{4}{7}\)=\(\frac{11}{14}\)
4,5-2x =\(\frac{11}{14}:\frac{11}{7}\)
-2x =\(\frac{1}{2}\)
x=-1/4
a)(2,8x-32):\(\frac{2}{3}\)=-90
2,8x-32=-90.\(\frac{2}{3}\)
2,8x =-60+32
x =-28:2,8
x=-10
b)(4,5-2x).1\(\frac{4}{7}\)=\(\frac{11}{14}\)
4,5-2x =\(\frac{11}{14}:\frac{11}{7}\)
-2x =\(\frac{1}{2}\)
x=-1/4
Tìm x biết
(2,8x - 32) : \(\frac{2}{3}\)= -90
(4,5 - 2x) . \(1\frac{4}{7}\)= \(\frac{11}{14}\)
Tìm x, biết:
a) (2,8x-32):\(\frac{2}{3}\)= -90
b) (4,5-2x).1\(\frac{4}{7}\)= \(\frac{11}{14}\)
Tìm x, biết :
\(\left(2,8x-32\right)\div\frac{2}{3}=-90\)
\(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)
Tìm x, biết:
a) (2,8x - 32) : 2/3 = -90
b) (4,5 - 2x) . 1 4/7(hỗn số) = 11/14
1. Tính giá trị biểu thức:
\(A=-1,6:\left(1+\frac{2}{3}\right)\)
\(B=1,4.\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):2\frac{1}{5}\)
2. Tìm x:
a, \(\left(2,8x-32\right):\frac{2}{3}=-90\)
b, \(\left(4,5-2x\right).1\frac{4}{7}=\frac{11}{14}\)
( 2,8x -32 ) : \(\frac{2}{3}\) = -90 ( 4,5 - 2x ) . 1\(\frac{4}{7}\) = \(\frac{11}{14}\)
Tìm x:
a, x + 30%x = -1,31
b,\(\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
c, \(\frac{1}{2}x-\frac{3}{4}=\frac{14}{9}.\frac{3}{7}\)
d,\(\frac{-5}{6}-x=\frac{7}{12}+\frac{-1}{3}\)
e,\(\frac{x+3}{-15}=\frac{1}{3}\)
f,\(\left(4,5-2x\right).\left(-1\frac{4}{7}\right)=\frac{11}{14}\)
GIÚP MIK LM TRONG TỐI NAY NHA, MAI MIK PHẢI NỘP RỒI
tìm x, biết
a, (2,8x - 32) : \(\frac{2}{3}\)= -90
b, \(\frac{4}{5}\)+\(\frac{5}{7}\): x = \(\frac{1}{6}\)
tìm x
\(|x+3|\div\left(-15\right)=\frac{1}{3}\)
\(|4,5-2x|\cdot(-1\frac{4}{7})=\frac{-11}{14}\)
giúp mình với mai mình nộp rồi