\(\dfrac{8}{5}-x+\dfrac{4}{5}=\dfrac{6}{3}\)
\(\dfrac{8}{5}-x=\dfrac{6}{3}-\dfrac{4}{5}\)
\(\dfrac{8}{5}-x=\dfrac{30}{15}-\dfrac{12}{15}\)
\(\dfrac{8}{5}-x=\dfrac{18}{15}\)
\(x=\dfrac{8}{5}-\dfrac{18}{15}\)
\(x=\dfrac{24}{15}-\dfrac{18}{15}\)
Vậy \(x=\dfrac{6}{15}\)