\(7,5-3\left|5-2x\right|=-4,5\)
\(\Leftrightarrow3\left|5-2x\right|=7,5-\left[-4,5\right]\)
\(\Leftrightarrow3\left|5-2x\right|=7,5+4,5\)
\(\Leftrightarrow3\left|5-2x\right|=12\)
\(\Leftrightarrow\left|5-2x\right|=4\)
\(\Leftrightarrow\orbr{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{9}{2}\end{cases}}\)
\(7,5-3\left|5-2x\right|=-4,5\)
\(\Leftrightarrow3\left|5-2x\right|=7,5-\left(-4,5\right)\)
\(\Leftrightarrow3\left|5-2x\right|=7,5+4,5\)
\(\Leftrightarrow3\left|5-2x\right|=12\)
\(\Leftrightarrow\left|5-2x\right|=12:3\)
\(\Leftrightarrow\orbr{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=5-4\\2x=5-\left(-4\right)\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=1\\2x=9\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=1:2\\x=9:2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=\frac{9}{2}\end{cases}}\)
~ Rất vui vì giúp đc bn ~
\(3|5-2x|=7,5-\left(-4,5\right)\)
\(3\left|5-2x\right|=12\)
\(\left|5-2x\right|=12:3\)
\(\left|5-2x\right|=4\)
\(\Rightarrow\)\(\hept{\begin{cases}5-2x=4\\5-2x=-4\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}2x=5-4\\2x=5-\left(-4\right)\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}2x=1\\2x=9\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=1:2\\x=9:2\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=0,5\\x=4,5\end{cases}}\)
Vậy \(x=0,5\)hoặc \(x=4,5\)
